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Given the following information, what is the percent error for the results of this titration?
What's the best way to deal with this in Lon-Capa? Bear in mind that we are dealing here with experimental results, so they could vary quite a bit. It does not seem practical therefore to set the tolerance to an absolute value, but in the case where the actual result should be zero, only a percent tolerance of 100% will include zero. Is there a practical method to force an answer, when it turns out to be the result of the computer's floating point inaccuracies, to be rounded off to what is reasonable?